Matrix dimensions

Viewing 2 posts - 1 through 2 (of 2 total)
  • Author
  • #7724

    Dear Stefan,
    Hope you are fine and well.
    Please I need help in the following:
    I want to use another type of inversion algorithm instead of Matlab command (inv()) for the following equations:
    h1 = inv(sigma_n2*inv(C_h+10000*eps*eye(nLayers*N)) + R1’*R1) * (R1)’*y1;
    h2 = inv(sigma_n2*inv(C_h+10000*eps*eye(nLayers*N)) + R2’*R2) * (R2)’*y2;

    But I want to make the dimension of matrices (n) to be the powers of two (n= 2^0 ,2^1,2^2,2^3,2^4……etc.) for my inversion algorithm to work.

    Please how can do that and where the change will be to achieve Matrix dimensions with power of 2 ?

    Kind regards




    as you see, the matrix dimensions are given by nLayers*N x nLayers*N. This means, they are square and the size is given by the number of subcarriers N and the number of active spatial layers nLayers. You cannot directly choose this size. According to the schedule, this size will be a multiple of 12 since scheduling is done in terms of resource blocks.


Viewing 2 posts - 1 through 2 (of 2 total)
  • The forum ‘Vienna LTE-A Uplink Link Level Simulator’ is closed to new topics and replies.